Question

A particle of mass M strikes with a ball at speed v and returns with same speed change in linear momentum of a particle is what​

Answer 1

Answer:

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Answer 2

ANSWER IS 2Mv

Explanation:

LET US CONSIDER THE SIDE IN WHICH THE BALL WAS TRAVELING BEFORE COLLISION AS +VE AND THE OTHER SIDE AS NEGATIVE..

ACCORDING TO THE LAW OF CONSERVATION OF LINEAR MOMENTUM...

P1 = P2.... Intial momentum is equal to final momentum..

initial momentum = mass × initial velocity=Mv

final momentum = mass × final velocity= M×-v because we consider it as -ve direction...

Therefore change in linear momentum= P2 - P1

therefore the change is -Mv-Mv.

Magnitude wise it is 2Mv..