A particle of mass m with an initial velocity ui collides
perfectly elastically with a mass 3m at rest. It moves with a
velocity vj after collision, then, v is given by:
Answers
Answered by
2
Answer ⤵️
From conservation of linear momentum, mv=mv
B
+
2
m
v
B
v=v
A
+
2
v
B
Also v
2
=v
a
2
+
2
v
B
2
(v
A
+
2
v
B
)
2
=v
A
2
+(
2
v
B
)
2
v
A
v
B
=
4
v
B
v
B
=4v
A
and m
B
=
2
m
A
P
A
=m
A
v
A
P
B
=
2
m
A
×4v
A
=2P
A
λ
B
λ
A
=
P
A
P
B
=
P
A
2P
A
=2
Similar questions