Physics, asked by dagars601, 1 day ago

A particle of mass m1, is kept at x=0 and another of mass m2 at x=d. When a third particle is kept at x=d/4, it experiences no net gravitational force due to the particle. Find m2 /m1.

Answers

Answered by whitedevil3002
1

Answer:

m2 : m1 = 9 : 1

Explanation:

see the pic

And if it helped then mark me as brainliest...

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