Question

A particle of mass m1 is moving with velocity v1 and another particle of mass m2 is moving with a velocity of v2 both of them have the same momentum but their different kinetic energies are E1 and E2 resp. if m1>m2 then

Answer 1

Then E1<E2 and therefore v1<v2.
Approach the question using relation
momentum p = √(2*m*E).

Answer 2

Answer:

E1/E2 =M2/M1

Explanation:

kinetic energy = (momemtum)square/2m

therefore KE =1/M

SO KE1/KE2=M2/M1