Math, asked by comando123, 1 year ago

A particle of mass m1 moving with velocity u makes a heat on collision with a particle of mass m2 initially at rest , so that their final velocity v1 and v2 are along the same line .

If the collision is elastic show that

 \large{v} \tiny{2} \large \:  =  \frac{2u}{1 + ( \frac{m1}{m2}) }

and also calculate the fraction of total energy shared by m2.


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Answers

Answered by fanbruhh
73

 \huge \bf \red{ \mid{ \overline{ \underline{ANSWER}}} \mid}

 \bf{solution = }

By the principle of conservation of momentum and energy,

→ momentum before impact = momentum after impact ______(1)

→ energy before impact = energy after impact _____(2)

Since in elastic collision , there is no loss of kinetic energy

m1u1+m2u2 = m1v1+m2v2.

For more solution please refer to pic .

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Answered by Anonymous
67
 \sf{\large {\underline {ELASTIC \:COLLISION \:IN\:ONE\:DIMENSION}}}

REFER THE ATTACHMENT.
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