A particle of small mass m is joined to a very heavy body by a light string passing over a light pulley. Both bodies are free to move. The total downward force on the pulley due to string is nearly
(A) mg
(B) 2 mg
(C) 4 mg
(D) can not be determined
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Answer:
C.)4mg
The heavy body will fall due to acceleration due to gravity.The acceleration of the lighter body will be 'g' in upward direction.Taking the equilibrium of the small body
T-mg=ma
but a=g
Therefore, T-mg=mg
T=2mg
Total reaction at the pulley
2T=4mg
Hence option (c) is correct.
Explanation:
Hope this answer will be helpful..
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