Question

A particle of unit mass undergoes one-dimensional motion such that its velocity varies according to v(x) = bx⁻²ⁿ where b and n are constants and x is the position of the particle. The acceleration of the particle as d function of x, is given by: (a) –2nb²x⁻⁴ⁿ⁻¹(b) –2b²x⁻²ⁿ⁺¹(c) –2nb²e⁻⁴ⁿ⁺¹(d) –2nb²x⁻²ⁿ⁻¹

Answer 1

hey dear

ur answer is ^_^

option no c

thanks

Answer 2

See the attachment.........