Question

A particle of velocity of 2m/s at t=0 moves along a straight line with a constant acceleration of 0.2m/s^2.Find the displacement of the particle in 10 seconds?

Answer 1

s = ut + at²/2

⇒s = 2 x10 + 0.2 x 100/2

⇒s = 20 + 10 

⇒s = 30 m ANSWER 

Answer 2

Answer:

Explanation:

Velocity of the particle = u =2m/s  (Given)

Time taken by the particle t = 10s  (Given)

Constant acceleration = a = 0.2m/s²  (Given)

Displacement refers to a vector quantity that refers as to how far out of place an object is. Displacement is the object's overall change in its position.

Using the second equation of motion -  

S = ut + 1/2at²

= 2 × 10 + 0.5 × 0.2 × 10 × 10

= 20+10

= 30

Thus, if a particle with a velocity of 2m/s a t=0 moves along a straight line with a constant acceleration of 0.2m/s2, then the displacement of that particle in first 10 seconds is 30m.