A particle on the stretched string supporting a travelling wave
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Her, I have presented the completion of your question.
A particle on a stretched string supporting a travelling wave, takes 5.0 ms to move from its mean position to the extreme position. The distance between two consecutive particles, which are at their mean positions, is 2.0 cm. Find the frequency, the wavelength and the wave speed.
The answer:
Time period,
T = 4 ×5 ms
= 20 × 10–3
T = 2 × 10–2 s
λ = 2 × 2 cm
λ = 4 cm
Frequency, f = 1/T
= 1/(2 × 10–2)
= 50 s–1
f = 50 Hz
Wave speed = λ
= 4 × 50
= 2000 cm/s
λ = 2 m/s
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