Question

A particle or mass m is projected with a velocity v an making angle 30° with the horizontal . the magnitude of angular momentum to the projectile about the point of projection when the particle is at it's maximum height h is [AIEEE 2011] ​

Answer 1

Explanation:- Angular momentum of the projectile as given by L = mvₕr⏊

• velocity 'v: = vcos¢

where ,h is maximum height

• 'h' = v²sin²¢/2g
• L = m (vcos¢)[v²sin²¢ /2g]
• L = mv³sin²¢cos¢ /2g
• given as angle 30° with the horizontal
• ∴ L = √mv²sin²30° cos30° / 2g
• L = √3mv³/16g Answer

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Answer 2

Answer:

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