A particle oscillates as per the equation x=(7cos0.5pie t)m, the time taken by the particle to move from the mean position to a point 3.5m away is ------
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Particle will take 2/3 s to travel the distance of 3.5 m
Explanation:
Maximum amplitude = 7 m
Angular velocity = ω = 0.5 π
2πT = 0.5 π
x = (7 cos 0.5 π t) m
3.5 = (7 cos 0.5 π ∝1 )
3.5 / 7 = cos 0.5 π ∝1
cos π / 3 = (cos 0.5 π ∝1)
π / 3 = 0.5 π ∝1
∝1 = 1 / 3 x 0.5 = 10 / 15 = 2/3 second
Therefore particle will take 2/3 s to travel the distance of 3.5 m
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A particle moves along a straight line OX. At a time t[u = in seconds ] the distance x [in m] of the particle from O is given by x= 40+12t-t^3.how long would the particle travel before coming to rest?
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