Question

A particle p is moving along a straight line with velocity 3m/s and another particle Q has a velocity 5m/s at an angle of 30 degree to the path of P calculate the velocity of Q relative to P

Answer 1

Answer:

,

Explanation:

fig will be like this,u can solve from this

Answer 2

Answer:

The velocity of Q relative to P is 2.83 m/s.

Explanation:

Given that,

Velocity of P = 3 m/s

Velocity of Q= 5 m/s

We need to calculate the velocity of Q relative to P

Using cosine rule

$v_{QP}=\sqrt{v_{Q}^2+v_{p}^2-2v_{Q}v_{P}\cos\theta}$

Where, $v_{Q}$ = velocity of Q

$v_{P}$ = velocity of P

Put the value into the formula

$v_{QP}=\sqrt{5^2+3^2-2\times5\times3\cos30}$

$v_{QP}=2.83\ m/s$

Hence, The velocity of Q relative to P is 2.83 m/s.