Question

A particle p is moving with a constant speed of 6 metre per second in a direction to i - j cap - 2 k cap 20 is equal to zero is at a point whose position vector is 3 icap + 4 j cap - 7 k cap find the position vector of a particle p after 4 seconds

Answer 1

Explanation:

The position of the Vector can find by using If the linear momentum of any particle is p=mv and its position vector from any constant point be r then abgular momentum of the particle is given by

L = r×p = m(r×v) (1)

Angular momentum is a vector quantity and its direction is perpandicular to the direction of r and p and could be found out by right hand screw rule.

From equation 1 scalar value or magnitude of angular momentum is given as

|L|=rpsinθ (2)

where V is the angle between r and p.

For a particle moving in a circular path

v=ω×r; (3)

where ω is the angular velocity