Physics, asked by adityamishra603, 8 months ago

A particle P is projected from a point on the surface of smooth inclined plane (see figure). Simultaneously another
particle Q is released on the smooth inclined plane from the same position. P and Q collide on the inclined plane after
t = 4 second. The speed of projection of P is : (in m/s)

Answers

Answered by Tanisha1234
1

Answer:

Explanation:

Hello Friend,

ANSWER

Relative velocity of a particle P in the frame of Q changes linearly with time during the flight of P

Acceleration of Particle P and Q along the inclined is same

Acceleration of particle P perpendicular to the incline plane =10 cos60

                                                                                                    =10 × 1/2

                                                                                                   =5 m/sec  square

So

V p −5(2)=0

V p  = 10 m /s

Hence speed of projection of P is 10 m/sec.

               

                                                                                                   

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