A particle P is projected from a point on the surface of smooth inclined plane (see figure). Simultaneously another
particle Q is released on the smooth inclined plane from the same position. P and Q collide on the inclined plane after
t = 4 second. The speed of projection of P is : (in m/s)
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Explanation:
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ANSWER
Relative velocity of a particle P in the frame of Q changes linearly with time during the flight of P
Acceleration of Particle P and Q along the inclined is same
Acceleration of particle P perpendicular to the incline plane =10 cos60
=10 × 1/2
=5 m/sec square
So
V p −5(2)=0
V p = 10 m /s
Hence speed of projection of P is 10 m/sec.
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