Question

A particle P is projected vertically upward from a point in 6 seconds later and the particle Q is projected vertically upward from point a both P and Q reach A simultaneously. the ratio of maximum height reached by p and q = 64:25 find the velocity of the projection of Q
in m/s​

Answer 1

Answer:

5u/8

Explanation:

u =velocity of P

U=velocity of Q

h= height of P

H= height of Q

we know that,

h/H=64/25

u^2. ×. 2g. =. 64

2g. U^2. 25

from this we get ,

U=5u

8

Hope it helps............

..

.

.

.

please mark it as branliest ...

Answer 2

Answer:

according to the question answer is given