A particle P is projected vertically upward from a point in 6 seconds later and the particle Q is projected vertically upward from point a both P and Q reach A7 10 asleep the ratio of maximum height reached by p and q = 64:25 find the velocity of the projection of you in m/s
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Time taken will be time of ascent given by u/g
Where u is intial velocity and g is acceleration due to gravity
So T=10/9.8=1.02 seconds
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