Question

A particle performing S.H.M. of amplitude 8 cm covers a distance of 4 cm in the first
second after starting from rest. The distance covered by the particle in fifth second is:
a) 4 cm
b) 2 cm
c) 12 cm
d) 8 cm​

Answer 1

Answer:

4

a= A sin (Omega* time)

Explanation:

4= 8 Sin (Omega*time)

Answer 2

Hello Friend..!!

The answer of u r question is..!!

Option.A

Thank you..!!