Physics, asked by sbvlogs16, 4 days ago

A particle performing uniform circular motion has an angular momentum L. What will be its angular momentum, if its angular frequency is halved and kinetic energy is doubled?

Answers

Answered by zpoihcvi

0

Answer:

The correct option is D L4

Kinetic energy in rotation is K=12Iω2=12(I×ω)×ω

⇒K=12Lω

⇒L=2Kω

So, L2L1=K2K1×ω1ω2=12×12

⇒L2L1=14

L2=L4

Explanation:

hope it helps you buddy!.

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