A particle performs linear S.HM. of period 4 sec and amplitude 4cm.Find the time taken by it to travel a distance of 1 cm from the positive extreme position?
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A particle executing SHM of amplitude 4cm and T=4s. The time taken by it to move from positive extreme position to half the ... Amplitude A and time period T of both the particles are equal. At t=0 ... A particle performs SHM with a frequency of 1/2 Hz. If the time is ... Get your doubts solved instantly for free.
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Answer:
Time=0.66 sec
Explanation:
Time period =4 sec Amplitide = 4 cm
Distance=1 cm
Formula of angular velocity
w=2pie/4
w=pie/2
We need to calculate time
wt=pie/3
t=pie/3×2/pie
t=2/3
t= 0.66 sec
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