Physics, asked by dishapatel6203, 10 months ago

A particle performs SHM of amplitude 20 cm and has a maximum velocity 200 cm per second what is the displacement when the velocity is 120 cm per second

Answers

Answered by RishiAEC

2

Answer:

v = dxdt = Aω cos(ω t + θ) Maximum v occurs for maximum value of cos(ω t + θ) , which is 1Thus, maximum v = Aω Now, ω = 2πT = 2π2 = π , and A.

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