Physics, asked by Lavanyawarwatkar2004, 14 hours ago

A particle performs UCM. The diameter of the circle is 4 cm. What is the amplitude of linear SHM that is the projection of the UCM on a diameter.​

Answers

Answered by krishnapatel226002
1

Answer:

17_87289=892+919385910209358

Answered by shilpa85475
0

Particle making UCM:

  • Particles that form a circular motion similar to angular L.
  • If its angular frequency is doubled and its kinetic energy is halved, then the new angular force is Rotational Kinetic Energy = ½Iω 2.
  • Circle diameter 4 cm:
  • Radius circle = 2 or width = 4 or circle = 12.57 cm has space
  • 1.257 × 10-9 square kilometers (km²) 0.001257 square meters (m²)
  • 12.57 square centimeters (cm²) 1257 square millimeters (mm²)
  • 4.8533 × 10-10 square miles (mi²) 0.00150336 square meters (yd²) 0.0135302 square feet (ft²) 1.94835 square meters (in²).
  • The amplitude of the SHM line which is the UCM projection in width: ²).
  • From scales (1) and (2), we can say that the base of perpendiculars X and Y use SHM on the x-axis and the y-axis respectively.
  • The amplitude of SHM is R and the angular frequency is ω.
  • Thus, the speculation of the particles that make up the UCM, at any diameter, is SHM.
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