Question

A particle projected from origin moves in xy plane with velocity 3 ICAP + 6J cap find equation of path followed​

Answer 1

Answer:

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Explanation:

GIVEN:

V=3i+6xj

V=dx/dt i + dy/dt j

dx/dt =3.........(1)

dy/dt=6x........(2)

Take eq.(1)....

dx=3.dt

Integrate both sides,we get-

x=3t .......(3)

Take eq.(2).....

dy=6x.dt

Put value of x from eq.(3)--

dy=6(3t).dt

dy=18t.dt

Integrate both sides,we get-

y=9t^2

Value of t from eq.(3) ..

t=x/3

y=9(x/3)^2

y=x^2

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