Question

a particle projected from origin moves in xy plane with a velocity

Answer 1

So,

If the projectile is thrown at an angle Ф with a velocity of u in the x-y plane

I'm assuming we have to find the range , maximum height and time taken during the flight for the projectile ,

Now,

Ux and Uy are the velocity components in x and y direction

H=Uy²/2g

H= (u² sin²Ф )/ 2g

For the info, Height will be maximum when angle Ф = 45°

R= (2 × Ux × Uy)/ g

R= ( u² × sin2Ф) /g

Time of flight

T= (2 × Uy)/ g

T= (2 × u sinФ)/ g