Question

A particle revolves along a rotational/circular path with a constant angular velocity.The position vector of this particle is: vec r(t)=that are(to) Where hat r(t)=cos theta hat imath+sin theta hat jmath theta=omega t Obtain the velocity and acceleration vectors of the particle and calculate their magnitudes.Angular velocity is denoted by omega and theta by theta Consider that the center of the circle is at original point O .The magnitude of vec r remains constant and the unit vector hat r(t) rotates at a constant rate.A rotational motion is a 2D motion such as plane polar coordinates.​

Answer 1

Answer:

A particle revolves along a rotational/circular path with a constant angular velocity.The position vector of this particle is: vec r(t)=that are(to) Where hat r(t)=cos theta hat imath+sin theta hat jmath theta=omega t Obtain the velocity and acceleration vectors of the particle and calculate their magnitudes.Angular velocity is denoted by omega and theta by theta Consider that the center of the circle is at original point O .The magnitude of vec r remains constant and the unit vector hat r(t) rotates at a constant rate.A rotational motion is a 2D motion such as plane polar coordinates.

Explanation:

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