Question

A particle revolves in clock wise direction (as seen from point A) in a circle C of radius 1 cm and completes one revolution in 2 sec. The axis of the circle and the principal axis of the mirror M coincide. The radius of curvature of the mirror is 20cm. Then the speed of the image (as seen from A in cm/s) is

Description: 0.jpg​

Answer 1

Answer:

Given, u=−10 ;f=+10

From mirror formula,

v

1

+

u

1

=

f

1

v

1

+

10

−1

=

10

1

v=+5

magnification is −

u

v

=−

−10

5

=0.5

radius of image is 0.5×1=0.5cm

time period is 2 sec

T=

ω

2π

=2

ω=π

velocity=radius×ω=0.5×π=1.57

and the direction remains same as that of the object i.e, clockwise.