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A particle slides back and forth between two inclined frictionless planes joined smoothly at the bottom. The time period of the motion

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Answered by Abignya
1

Explanation:

A particle slides back and forth between two inclined frictionless planes joined smoothly at the bottom. The time period of the motionA particle slides back and forth between two inclined frictionless planes joined smoothly at the bottom. The time period of the motionA particle slides back and forth between two inclined frictionless planes joined smoothly at the bottom. The time period of the motionA particle slides back and forth between two inclined frictionless planes joined smoothly at the bottom. The time period of the motionA particle slides back and forth between two inclined frictionless planes joined smoothly at the bottom. The time period of the motionA particle slides back and forth between two inclined frictionless planes joined smoothly at the bottom. The time period of the motionA particle slides back and forth between two inclined frictionless planes joined smoothly at the bottom. The time period of the motionA particle slides back and forth between two inclined frictionless planes joined smoothly at the bottom. The time period of the motionA particle slides back and forth between two inclined frictionless planes joined smoothly at the bottom. The time period of the motionA particle slides back and forth between two inclined frictionless planes joined smoothly at the bottom. The time period of the motionA particle slides back and forth between two inclined frictionless planes joined smoothly at the bottom. The time period of the motion

Answered by Anonymous
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PHYSICS

If a particle slides back and forth between two smooth planes as shown in the figure, then the correct statement is/are:

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ANSWER

By equation of motion

d=ut+

2

1

at

2

sinθ

h

=(0)t+

2

1

(g sinθ)t

2

t=

g sin

2

θ

2h

=

sinθ

1

g

2h

So, this much time is taken to reach at bottom from h height so, time period will be 4t=

sinθ

4

g

2h

So, its is an oscillatory motion with time period

sinθ

4

g

2h

.

It is not SHM because force is not proportional to displacement, it is constant of magnitude mg sinθ

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