Physics, asked by swaranalathareddy8, 8 months ago

A particle slows down from a speed v0 while moving in a straight line if declaration is directly proportional to the particle its displacement as a function of time is (k is proportionality constant) ​

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Answered by Anonymous
5

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let a is the magnitude of deceleration .

and v is the speed of particle .

a/c to question,

a =K√v { where K is the constant

dv/dt =K√v

dv/√v = K.dt

integrate both sides ,

[ 2√v ] = K [ t ] put the limit

2[ √v - √vo ] = Kt

2√v = kt + 2√vo

√v ={ kt + 2√vo }/2

v = { K/2.t + √vo }²

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