Physics, asked by venkateshvvg9, 7 months ago

.A particle slows down from a speed v0 while moving in a straight line. If declaration is direct proportional to the particle its displacement as a function of time is ( K is proportionality constant )​

Answers

Answered by nishadhani7
0

Explanation:

The average velocity is given as:

v

av

=

t

s

=

Totaltime

Totaldisplacement

We know a = v

ds

dv

⇒ v dv = a ds

Let us calculate the displacement by substituting a = −α

v

(for retardation) in vdv = a ds.

We have v dv = (−α

v

ds ⇒

v

dv = −αds

When the particle slows down from v

0

to 0, it covers a distance s.

Hence, ∫ v in0

0

v

dv=−∫

0

s

αds

This gives s =

2v

0

3/2

Now we will find the time of motion by substituting a = −α

v

in a =

dt

dv

, we get

−α

v

=

dt

dv

v

dv

=−αdt

If the particle takes time t to stop, we have

v

0

0

v

dv

=−α∫

0

t

dt

This yields t =

α

v

0

Finally, substituting s and t in v

av

= s/t, we have

v

av

=

3

2v

0

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