Question

a particle start from the origin, goes along x_axis to the point (10m,0) and then return along the same line to the point (-10m,0).the distance and displacement of the particle during the trip how​

Answer 1

Answer:

It's pretty simple.

The distance traveled = 10 (origin to (10,0)) + 20 ((10,0) to (-10,0)) = 30 m

the displacement = -10 m

Here negative sign represe

Only consider the starting point and the end point to get the solution.

x is the direction of movement.

Answer 2

Answer:

distance covered=10+10+10=30m

Displacement=-10m

Explanation:

1.First the particle goes 10m(0 to 10 on x axis)then it goes 10m [10 to 0(origin)].And then goes 10m[0 to (-10)]

i.e.the particle travels10+10+10=30m.

2.Displacement is initial postion to final position.i.e.0 to -10=-10m.