a particle start moving with velocity 11m/sec in a straight line with constant retardation 2 m/sec2. find distance covered in first 5 second ?
Answers
Answered by
1
U = 11 m/s
A = -2m/s^2
time = 5 sec.
S = ut + 1/2at^2
= 11*5 + 1/2*-2*25
= 55 - 25
= 30 m ans.
A = -2m/s^2
time = 5 sec.
S = ut + 1/2at^2
= 11*5 + 1/2*-2*25
= 55 - 25
= 30 m ans.
Anonymous:
may be but i am not sure cuz i Read it in class 9th
i am going toask u a question just formally . may i ?
yes, why not
are u using fb ?
nope
ok no problem
and thnks once again.
ok.
:-)
hlw
Similar questions