Question

a particle start moving with velocity 9m/s it is extracted 3m/s^2. find distance travelled and displacement of particle after 6 sec.​

Answer 1

Answer:

Hope it will help u . Displacement will be the same but I am not sure about this

Answer 2

Answer:

u=9m/s

v=?

a=3m/s^2

t=6s

a=(v-u)/t

3×6=v-9

v=27m/s^2.

displacement =v×t=27×6=162m.

distance =162m.