Physics, asked by tebaiwaqar, 11 months ago

a particle start with constant velocity of 10ms-1 it covers distance 20m along a straight line in two seconds what is acceleration​

Answers

Answered by BrainIyMSDhoni
38

Answer:

Acceleration =0m/sec²

Hence the acceleration is 0 because the velocity remains constant.

Explanation:

Given:

Initial velocity of the particle = 10m/sec

Distance covered by the particle = 20m

Time taken by the particle = 2sec

Acceleration is the rate of change of velocity.

Here:

The initial velocity = final velocity.

So:

Acceleration =  \frac{final \: velocity - initial \: velocity}{time \: taken}

Hence:

Hence: Acceleration is 0 m/sec²

Or in other method :

Here:

In order to find the acceleration we will use 2nd equation of motion i.e

S = ut +  \frac{1}{2}  {at}^{2}

Where:

s is the distance,

u is initial velocity,

a is acceleration and

t is the time taken.

Now:

Putting the required values in the equation we get,

 =  > 20 = 10 \times 2 +  \frac{1}{2} a \times  {2}^{2}  \\  =  > 20 = 20 +  \frac{1}{ \cancel2}  \times a \times 2 \times  \cancel2 \\  =  > 20 - 20 = 2a \\  =  > 0 = 2a \\  =  >  \boxed{a = 0}


BrainlyRacer: Nice bro!!
Answered by BrainlyRacer
27

               ✪Full Explanaion✪

After the solution of this question  

we have to recape that 'what is

acceleration? '

======================

Answer : The rate of change of velocity of

an object with respect to time is known

as acceleration.

======================

Now we have to recape the three

equations of motion.

  • v = u + at  
  • s = ut + 1/2 at²
  • v² = u² + 2as  

======================

Now come to the your question

★ Given :

   Initial velocity of particle (u) = 10 m/s

   Distance covered by particles (s) = 20 m

   Time taken (t) = 2 sec

======================

★ To find :

   Acceleration of given particle .

======================

    So,

    According to the question

    we have intial speed (u),

    distance (s) and time (t)

    ∴ here, we use second eq.

      of motion

======================              

★  Let's solve :

             ↳

             

                ⇒ s = ut + 1/2 at²

               ⇒20 = 10 × 2 + 1/2a ×  (2)²

               ⇒20 = 10 × 2 + 1/2a × 4

               ⇒20 = 20 + 2a

              ⇒20-20 = 2a

              ⇒0 = 2a

          ∴ a = 0 m/s²

======================

✸Answer :

  0 m/s²

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