a particle start with constant velocity of 10ms-1 it covers distance 20m along a straight line in two seconds what is acceleration
Answers
Answer:
Acceleration =0m/sec²
Hence the acceleration is 0 because the velocity remains constant.
Explanation:
Given:
Initial velocity of the particle = 10m/sec
Distance covered by the particle = 20m
Time taken by the particle = 2sec
Acceleration is the rate of change of velocity.
Here:
The initial velocity = final velocity.
So:
Hence:
Hence: Acceleration is 0 m/sec²
Or in other method :
Here:
In order to find the acceleration we will use 2nd equation of motion i.e
Where:
s is the distance,
u is initial velocity,
a is acceleration and
t is the time taken.
Now:
Putting the required values in the equation we get,
✪Full Explanaion✪
After the solution of this question
we have to recape that 'what is
acceleration? '
======================
Answer : The rate of change of velocity of
an object with respect to time is known
as acceleration.
======================
Now we have to recape the three
equations of motion.
- v = u + at
- s = ut + 1/2 at²
- v² = u² + 2as
======================
Now come to the your question
★ Given :
Initial velocity of particle (u) = 10 m/s
Distance covered by particles (s) = 20 m
Time taken (t) = 2 sec
======================
★ To find :
Acceleration of given particle .
======================
So,
According to the question
we have intial speed (u),
distance (s) and time (t)
∴ here, we use second eq.
of motion
======================
★ Let's solve :
↳
⇒ s = ut + 1/2 at²
⇒20 = 10 × 2 + 1/2a × (2)²
⇒20 = 10 × 2 + 1/2a × 4
⇒20 = 20 + 2a
⇒20-20 = 2a
⇒0 = 2a