a particle starting at rest.and its acceleration is 20 cm/ sec2. than the calculate the distance in first 8 sec.
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therefore from the photo , the distance is 6.4m
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initial velocity= u= 0
accelaration= 20 cm/ s²
time= 8 seconds
using the second equation of motion,
s= ut + 1/2 at²
s= 0 x 8 + 1/2 x 20 x 8 x 8
s= 0+ 640
s= 640 cm
therefore, the distance traveled by the particle is 640 cm.
accelaration= 20 cm/ s²
time= 8 seconds
using the second equation of motion,
s= ut + 1/2 at²
s= 0 x 8 + 1/2 x 20 x 8 x 8
s= 0+ 640
s= 640 cm
therefore, the distance traveled by the particle is 640 cm.
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