Question

A particle starting from rest
acquires velocity of 100 m/s in
25s, then what is the acceleration of
the particle ?​

Answer 1

Answer:

Acceleration (a) = 4m/s

Explanation

velocity (v) = 100m/s

time (t) = 25s

particle is at rest

then

initial velocity (u) = 0

As we know that

a = v-u/t

a = 100 - 0/ 25

a = 100/ 25

a = 4m/ s

Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Acceleration=4\:m/s^{2}}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{Given :}} \\ \tt: \implies Final\:velocity(v) = 100 \: m/s \\ \\ \tt: \implies Time (t ) = 25 \: sec \\ \\ \red{\underline \bold{To \: Find:}} \\ \tt: \implies Acceleration(a) =?$

• In the given question information given about acquire velocity of particle which is 100 m/s in 25 sec from rest (initially u = 0).

• We have to find the acceleration of particle

• According to given question :

$\tt \circ \: Initial \: velocity = 0 \: m/s \\ \\ \bold{As \: we \: know \: that} \\ \tt: \implies v = u + at \\ \\ \bold{Here : } \\ \tt \circ \: v = 100 \: m/s \\ \\ \tt \circ \: t = 25 \: sec \\ \\ \tt \circ \:u = 0 \: m/s \\ \\ \tt: \implies 100 = 0 + a \times 25 \\ \\ \tt: \implies 100 = 25 \times a \\ \\ \tt: \implies a = \frac{100}{25} \\ \\ \green{\tt: \implies a = 4 \: {m/s}^{2} } \\ \\ \green{\tt \therefore Acceleration \: of \: particle \:is \: 4 \: {m/s}^{2} }$