Question

A particle starting from rest from o accelerates uniformly along a straight line and in 2 sec crosses two points A and B, which are 5 m apart. If the velocity at B is 2m/sec more than the velocity at A,find the distance OA.

Answer 1

Answer:

2 a s = v2^2 - v1^2      fundamental equation for rectilinear motion

a = (v2 - v1) / t         acceleration of particle

2 * (v2 - v1) / t)  * 5 = v2^2 - v1^2

5 = v2 + v1      substitute for t and divide both sides by (v2 - v1)

5 = v1 + 2 + v1    

v1 = 1.5 so v2 = 3.5

Answer 2

Answer:

I don't knew the answer

Step-by-step explanation:

thanks for the points friend..