Question

A particle starting from rest is accelerated by 4m/s^2. find the displacement of the body at 10^th second s=a÷2[2n_1]​

Answer 1

Step-by-step explanation:

The distance traveled by the particle in the last 2 seconds = distance traveled by particle in nth second- distance traveled by particle in (n-2)th second

So,

s=

2

1

an

2

−

2

1

a(n−2)

2

s=

2

1

a[n

2

−n

2

+4n−4]

s=

2

a

[4n−4]

s=(2n−2)a=2a(n−1).........(1)

Now,

Velocity, v=acceleration×time

v=a×n

a=

n

v

...........................(2)

Substitute value of 'a' from (2) to (1) we get,

s=

n

2v(n−1)