Question

A particle starting from rest moves with a constant angular acceleration alpha

Answer 1

Answer:

As we realize that Centripetal speeding up = v^2/r To start with condition of movement ω = ωo+ αt As beginning rakish speed is 0

Answer 2

Explanation:

As we realize that  

Centripetal speeding up = v^2/r  

To start with condition of movement  

ω = ωo+ αt  

As beginning rakish speed is 0  

ω = αt  

v/r = 4t  

v = 4tr.  

Extraneous increasing speed = centripetal quickening  

αr = a  

4r = v^2/r  

4r = (4tr)2/r  

4 = 16t^2  

t = ½  

t = 0.5 sec.