Question

a particle starting from rest moves with constant acceleration of 5 ms^-2 .the displacement covered in 3rd second of its motion will be

Answer 1

We know the distance travelled in
Snth second = u + 1/2a(2n-1)

ATQ ...
u = 0 { as the particle starts from rest
a = 5m/s^2
n = 3

so, Sn = 0+1/2(5)(2×3-1)
= 25/2