Question

A particle,starting from rest moves with constant acceleration 4 ms–2.the distance travelled by the particle in 5th second is​

Answer 1

Answer:

0.08m

Explanation: Given a= 4m/$s^{2}$ , u= 0m/s, t= 0.2s

Now use equation of motion s= ut+1/2a$t^{2}$

the initial velocity = 0 since the object started from rest

so :    s =  0(t) + 1/2a$t^{2}$

         s = 0.5 x 4 x $(0.2)^{2}$

         s = 0.08 m