Question

A particle starting from rest travels with constant acceleration for 20 seconds. if particle travels distance x in first 10 seconds and distance y in last 10 seconds, then the relationship between x and y is *

Answer 1

Answer:

Here is your answer.....

Answer 2

Answer:

The answer is y=3x

Explanation:

u=0 [ since body starts from rest ]

x = ut + 1/2*at^2

x = 0 + 1/2*a*10^2

x = 50a                 .................(1)

y = total distance - x

y = ut + 1/2*at^2 - x

y = 0 + 1/2*a*20*20 - x

y = 200a - x

y = 200a - 50a              [ x=50a from (1)]

y = 150a

x=50a

y=150a                      [solved above]

y/x = 150a/50a

y/x = 3

y = 3x

Answer : y = 3x

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