Question

A particle starting with a velocity 7m/s covers a distance of 80m reaching a velocity
19m/s, then acceleration and time of journey.....​

Answer 1

Answer:

initial velocity, u =7m/s

distance , s = 80m

final velocity , v =19m/s

a = ?

t = ?

Explanation:

2as=v^2-u^2

a=v^2-u^2/2s

a=19^2-7^2/2*80

a=361-49/160

a=312/160

a=39/20

a=1.95m/s^2

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Answer 2

Answer:

a=1.95 m/s^2

t=6.15 sec

Explanation:

use v^2-u^2=2as Put values we get

a=312/160=1.95 m/s^2

now use v=u+at

t=12/1.95=6.1538 sec