Physics, asked by milky555, 11 months ago

a particle starts at 4m/s and accelerates at a=-2t m/s2 . find distance covered in first 4s

Answers

Answered by shristy597
0
the disance covered in 4s is 32 m

milky555: how??
shristy597: initial velocity =4m/s. acceleration 2m/s2 time =4s distance =??
shristy597: s=ut +1/2at2
shristy597: s=4×4+1/2×2×4×4
shristy597: 4×4+4×4=16+16=32m
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