Question

A PARTICLE STARTS FROM (0,0) AND MOVES ALONG Y AXIS TO A POINT (0,25M) AND TO (0,-25M). THEN THE RATIO OF DISTANCE TO DISPLACEMENT

Answer 1

The distance covered by the particle is = 25 + 25 + 25  = 75m (ie from (0,0) to (0,25 then again back to (0,0) and back to (0,-25))

The displacement of the particle is = 25m (distance between (0,0) to (0,-25))

The ratio = 75/25 = 3

Answer 2

Answer:

The required ratio for the distance to displacement is found to be 3:1.

Step-by-step explanation:

The initial/starting point of the particle is given to us as (0,0), i.e., the point of origin in the cartesian plane. The particle is moving along the y-axis, i.e., the there is vertical displacement/distance.

So, we take the direction up the y-axis as positive and the opposite direction as negative. Now, the particle first travels to the point (0,25) and then travels 50 units down to the point (0,-25).

The distance covered by the particle will be given by:

$d=0+25-(-50)$

or we can say:

$d=75$ units

Now, the displacement of the particle will be the distance from the initial point and the ending point, which is:

$s=0-(-25)$

or we can say:

$s=25$ units

The ratio of the distance to the displacement of the particle is found to be:

$ratio=\frac{75}{25}=\frac{3}{1}=3:1$

The required ratio is found to be 3:1.