a particle starts from (0,0)and moves along y axis to a point (0,25m) and to point (0,minus25)then the ratio of magnitudes of distance to displacement is please answer me
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Explanation:
Given a particle starts from (0,0)and moves along y axis to a point (0,25 m) and to point (0, - 25)then the ratio of magnitudes of distance to displacement is
- Total distance travelled will be S = 0 to y1 = 25 + 25 and 0 to y2 = 25
- So 25 + 25 + 25 = 75 m
- Total displacement D = 0 toy1 – y1 to 0 + 0 to y2
- = 25 – 25 + 25
- = 25 m
- Magnitude of displacement = 25 m
- Therefore ratio will be distance / magnitude of displacement = S/D
- = 75 / 25
- = 3/1
- = 3: 1
Reference link will be
https://brainly.in/question/1630983
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