Question

A particle starts from a point with a velocity of + 6.0 m/per second and moves with an acceleration of -2.0 metre/second square . Show that after 6 second the particle will be at the starting point .

Answer 1

$using \: s = ut + \frac{1}{2} a {t}^{2} \\ s = 6(6) + \frac{1}{2} ( - 2) {(6)}^{2} \\ \: \: \: = 36 - \frac{1}{2} \times 36 \times 2 \\ \: \: \: = 36 - 36 \\ \: \: \: \: = 0 \\ thus \: displacement \: covered \: = 0 \\ so \: it \: is \: at \: original \: position$
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Answer 2

Explanation:

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