Question

A particle starts from a point with a velocity of +6.0m/s and moves with an acceleration of
-2.0m/s2
show that after 6s the particle will be at the starting point.

Answer 1

We have to find out final velocity
Vf=Vi+at
=(6)+(-2)(6)
=(6)-12
=-6m/s
6m/s is the final velocity and is initial velocity (starting point) for further traveling.

Not sure but i hope it may help you out

Answer 2

Gɪᴠᴇɴ

✭ Initial velocity (u) = 6m/s

✭ Acceleration (a) = -2 m/s²

✭ Time (t) = 6s

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Tᴏ ᴘʀᴏᴠᴇ

➤ The particle will be back at its starting point

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Sᴛᴇᴘꜱ

➠ So to prove that lets use the formula,

$\large { \underline{ \boxed{ \sf{s = ut + \frac{1}{2} a {t}^{2} }}}}$

❍ So substituting the given values,

$\large \tt \dashrightarrow{}s = 6 \times 6 + \frac{1}{2} \times ( - 2) \times {6}^{2} \\ \\ \large \tt \dashrightarrow{}s = 36 + ( - 36) \\ \\ \large \tt \dashrightarrow{}s = 0$

➜ So as the displacement of the body is 0 so then the body has come back to the same point where it started.

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