a particle starts from a point with a velocity of 6m/s and moves with qn acceleration of -2m/s . show that after 6s the particle will be at the starting point
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use s=ut +0.5at square...and put values s will be zero
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u=6m/s
v=0m/ s
a= -2 m/s
t= 6s
v= u +at
v= 6 m/s + -2m/s ×6s
-6 m/s
v=0m/ s
a= -2 m/s
t= 6s
v= u +at
v= 6 m/s + -2m/s ×6s
-6 m/s
xmessx:
thnks
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