Question

A particle starts from origin at time t=0 with velocity 8i m/s and moves in xy plane with constant acceleration of -2i+4j m/s2

Answer 1

Answer:

solved

Explanation:

x'' = -2

y'' = 4

x' = 8 - 2t

y' = 4t

x = 8t - t²

y = 2t²

t² - 8t = -x

t² - 8t +16 = 16-x

(t-4)² = 16 - x

t - 4 = ±√(16-x)

t  =   4 ± √(16-x)

y + 2x = 16t

y + 2x = 64 ± 16√(16-x)