A particle starts from origin, moves along x-axis to a point (8 m, 0) and then returns along the same line to another point (–12 m, 0). The ratio of magnitude of displacement to the distance travelled by the particle during the round trip is
Answers
Answer:
60 m,20 m in the negative direction
The starting point for the particle is origin as shown in figure.
The Distance traveled by the particle is:
D=20+20+20
=60m
The displacement is the distance between the initial and the final points.
Displacement ⇒OB=20m in the negative direction
The distance is 60 m and displacement is 20 m in negative direction
Explanation:
Given : A particle starts from origin, moves along x-axis to a point (8 m, 0) and then returns along the same line to another point (–12 m, 0).
To Find : The ratio of magnitude of displacement to the distance travelled by the particle during the round trip is
Solution:
Displacement = Final Position - Initial Position
Initial Position = (0, 0) origin
Final Position = ( -12m , 0)
Displacement = -12m - 0 = -12m
Magnitude of Displacement = | -12m |
= 12m ( assuming m is + ve)
Distance = | 8m - 0 | + | -12m - 8m | = | 8m| + | -20m |
= 8m + 20m
= 28m
The ratio of magnitude of displacement to the distance travelled by the particle during the round trip = 12m/28m
= 3/7
3/7 is the required answer
Note : Assuming m as -ve will not change the result just the final ratio will be - 12m / (-28 m ) = 3/7 ( as magnitudes are always non negatives)
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