A particle starts from origin, moves along x-axis to a point (8 m, 0) and then returns along the same line to another point (-12 m, 0). The ratio of magnitude of displacement to the distance travelled by the particle during the round trip is
Answers
Given : A particle starts from origin, moves along x-axis to a point (8 m, 0) and then returns along the same line to another point (–12 m, 0).
To Find : The ratio of magnitude of displacement to the distance travelled by the particle during the round trip is
Solution:
Displacement = Final Position - Initial Position
Initial Position = (0, 0) origin
Final Position = ( -12m , 0)
Displacement = -12m - 0 = -12m
Magnitude of Displacement = | -12m |
= 12m ( assuming m is + ve)
Distance = | 8m - 0 | + | -12m - 8m | = | 8m| + | -20m |
= 8m + 20m
= 28m
The ratio of magnitude of displacement to the distance travelled by the particle during the round trip = 12m/28m
= 3/7
3/7 is the required answer
Note : Assuming m as -ve will not change the result just the final ratio will be - 12m / (-28 m ) = 3/7 ( as magnitudes are always non negatives)
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